0=16x^2-72-8

Solution for 0=16x^2-72-8 equation:

0=16x^2-72-8

We move all terms to the left:

0-(16x^2-72-8)=0

We add all the numbers together, and all the variables

-(16x^2-72-8)=0

We get rid of parentheses

-16x^2+72+8=0

We add all the numbers together, and all the variables

-16x^2+80=0

a = -16; b = 0; c = +80;
Δ = b2-4ac
Δ = 02-4·(-16)·80
Δ = 5120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5120}=\sqrt{1024*5}=\sqrt{1024}*\sqrt{5}=32\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{5}}{2*-16}=\frac{0-32\sqrt{5}}{-32}
=-\frac{32\sqrt{5}}{-32}
=-\frac{\sqrt{5}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{5}}{2*-16}=\frac{0+32\sqrt{5}}{-32}
=\frac{32\sqrt{5}}{-32}
=\frac{\sqrt{5}}{-1}
$